(3x)^2=270

Solution for (3x)^2=270 equation:

(3x)^2=270

We move all terms to the left:

(3x)^2-(270)=0

a = 3; b = 0; c = -270;
Δ = b2-4ac
Δ = 02-4·3·(-270)
Δ = 3240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3240}=\sqrt{324*10}=\sqrt{324}*\sqrt{10}=18\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{10}}{2*3}=\frac{0-18\sqrt{10}}{6}
=-\frac{18\sqrt{10}}{6}
=-3\sqrt{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{10}}{2*3}=\frac{0+18\sqrt{10}}{6}
=\frac{18\sqrt{10}}{6}
=3\sqrt{10}
$